(编辑:jimmy 日期: 2024/12/28 浏览:2)
import numpy as np import pandas as pd data = [{'Name': '小明', 'Chinese': [70, 80], 'Math': [90, 80]}, {'Name': '小红', 'Chinese': [70, 80, 90], 'Math': [90, 80, 70]}] data = pd.DataFrame(data) data
def split_row(data, column): '''拆分成行 :param data: 原始数据 :param column: 拆分的列名 :type data: pandas.core.frame.DataFrame :type column: str ''' row_len = list(map(len, data[column].values)) rows = [] for i in data.columns: if i == column: row = np.concatenate(data[i].values) else: row = np.repeat(data[i].values, row_len) rows.append(row) return pd.DataFrame(np.dstack(tuple(rows))[0], columns=data.columns) split_row(data, column='Chinese')
from copy import deepcopy def split_col(data, column): '''拆分成列 :param data: 原始数据 :param column: 拆分的列名 :type data: pandas.core.frame.DataFrame :type column: str ''' data = deepcopy(data) max_len = max(list(map(len, data[column].values))) # 最大长度 new_col = data[column].apply(lambda x: x + [None]*(max_len - len(x))) # 补空值,None可换成np.nan new_col = np.array(new_col.tolist()).T # 转置 for i, j in enumerate(new_col): data[column + str(i)] = j return data split_col(data, column='Chinese')
1. 批量处理+不要原列
def split_col(data, columns): '''拆分成列 :param data: 原始数据 :param columns: 拆分的列名 :type data: pandas.core.frame.DataFrame :type columns: list ''' for c in columns: new_col = data.pop(c) max_len = max(list(map(len, new_col.values))) # 最大长度 new_col = new_col.apply(lambda x: x + [None]*(max_len - len(x))) # 补空值,None可换成np.nan new_col = np.array(new_col.tolist()).T # 转置 for i, j in enumerate(new_col): data[c + str(i)] = j split_col(data, columns=['Chinese','Math']) data
2. 带int和list数据
转成这样:
import numpy as np import pandas as pd data = [{'Name': '小爱', 'Chinese': 70, 'Math': 90}, {'Name': '小明', 'Chinese': [70, 80], 'Math': [90, 80]}, {'Name': '小红', 'Chinese': [70, 80, 90], 'Math': [90, 80, 70]}] data = pd.DataFrame(data) def split_col(data, columns): '''拆分成列 :param data: 原始数据 :param columns: 拆分的列名 :type data: pandas.core.frame.DataFrame :type columns: list ''' for c in columns: new_col = data.pop(c) max_len = max(list(map(lambda x:len(x) if isinstance(x, list) else 1, new_col.values))) # 最大长度 new_col = new_col.apply(lambda x: x+[None]*(max_len - len(x)) if isinstance(x, list) else [x]+[None]*(max_len - 1)) # 补空值,None可换成np.nan new_col = np.array(new_col.tolist()).T # 转置 for i, j in enumerate(new_col): data[c + str(i)] = j split_col(data, columns=['Chinese','Math']) data
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