Python 实现敏感目录扫描的示例代码
(编辑：jimmy 日期: 2024/11/12 浏览：2)
01 实现背景
1、PHPdict.txt，一个文本文件，包含可能的敏感目录后缀
2、HackRequests模块，安全测试人员专用的类Requests模块
02 实现目标
利用HackRequests模块，配合敏感目录字典PHPdict.txt，实现一个简单的敏感目录扫描Python文件
03 注意事项
1、输入URL时要输全：如 https://www.baidu.com/、 https://www.csdn.net/
2、为防止网站可能存在的简单反爬机制，我们简单添加headers信息，尝试绕过反爬
04 实现代码
import HackRequests
def HR(url):
h = HackRequests.hackRequests()
header = {
"Connection": "keep-alive",
"User-Agent":"Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:73.0) Gecko/20100101 Firefox/73.0"
}
try:
u = h.http(url=url,headers=header)
if u.status_code == 200:
print("%s is success!" %url)
else:
print("%s is failed! %d" %(url,u.status_code))
except:
pass
with open("C:\\Users\\Dell\\Desktop\\Python\\PHPdict.txt","r") as file:
lines = file.readlines()
urls = []
url_begin = input('请输入你要扫描的网站：')
for line in lines:
url = f'{url_begin}{line}'
urls.append(url)
for url in urls:
print(url)
HR(url)
05 实现效果
总结