(编辑:jimmy 日期: 2024/12/29 浏览:2)
前言
死锁的本质是资源竞争,批量插入如果顺序不一致很容易导致死锁,我们来分析一下这个情况。为了方便演示,把批量插入改写为了多条 insert。
先来做几个小实验,简化的表结构如下
CREATE TABLE `t1` ( `id` int(11) NOT NULL AUTO_INCREMENT, `a` varchar(5), `b` varchar(5), PRIMARY KEY (`id`), UNIQUE KEY `uk_name` (`a`,`b`) );
实验1:
在记录不存在的情况下,两个同样顺序的批量 insert 同时执行,第二个会进行锁等待状态
可以看到目前锁的状态
mysql> select * from information_schema.innodb_locks; +-------------+-------------+-----------+-----------+------------+------------+------------+-----------+----------+-----------+ | lock_id | lock_trx_id | lock_mode | lock_type | lock_table | lock_index | lock_space | lock_page | lock_rec | lock_data | +-------------+-------------+-----------+-----------+------------+------------+------------+-----------+----------+-----------+ | 31AE:54:4:2 | 31AE | S | RECORD | `d1`.`t1` | `uk_name` | 54 | 4 | 2 | '1', '1' | | 31AD:54:4:2 | 31AD | X | RECORD | `d1`.`t1` | `uk_name` | 54 | 4 | 2 | '1', '1' | +-------------+-------------+-----------+-----------+------------+------------+------------+-----------+----------+-----------+
在我们执行事务t1的 insert 时,没有在任何锁的断点处出现,这跟 MySQL 插入的原理有关系
insert 加的是隐式锁。什么是隐式锁?隐式锁的意思就是没有锁
在 t1 插入记录时,是不加锁的。这个时候事务 t1 还未提交的情况下,事务 t2 尝试插入的时候,发现有这条记录,t2 尝试获取 S 锁,会判定记录上的事务 id 是否活跃,如果活跃的话,说明事务未结束,会帮 t1 把它的隐式锁提升为显式锁( X 锁)
源码如下
t2 获取S锁的结果:DB_LOCK_WAIT
实验2:
批量插入顺序不一致的导致的死锁
------------------------ LATEST DETECTED DEADLOCK ------------------------ 181101 9:48:36 *** (1) TRANSACTION: TRANSACTION 3309, ACTIVE 215 sec inserting mysql tables in use 1, locked 1 LOCK WAIT 3 lock struct(s), heap size 376, 2 row lock(s), undo log entries 2 MySQL thread id 2, OS thread handle 0x70000a845000, query id 58 localhost root update insert into t1(a, b)values("2", "2") *** (1) WAITING FOR THIS LOCK TO BE GRANTED: RECORD LOCKS space id 55 page no 4 n bits 72 index `uk_name` of table `d1`.`t1` trx id 3309 lock mode S waiting Record lock, heap no 3 PHYSICAL RECORD: n_fields 3; compact format; info bits 0 0: len 1; hex 32; asc 2;; 1: len 1; hex 32; asc 2;; 2: len 4; hex 80000002; asc ;; *** (2) TRANSACTION: TRANSACTION 330A, ACTIVE 163 sec inserting mysql tables in use 1, locked 1 3 lock struct(s), heap size 376, 2 row lock(s), undo log entries 2 MySQL thread id 3, OS thread handle 0x70000a888000, query id 59 localhost root update insert into t1(a, b)values("1", "1") *** (2) HOLDS THE LOCK(S): RECORD LOCKS space id 55 page no 4 n bits 72 index `uk_name` of table `d1`.`t1` trx id 330A lock_mode X locks rec but not gap Record lock, heap no 3 PHYSICAL RECORD: n_fields 3; compact format; info bits 0 0: len 1; hex 32; asc 2;; 1: len 1; hex 32; asc 2;; 2: len 4; hex 80000002; asc ;; *** (2) WAITING FOR THIS LOCK TO BE GRANTED: RECORD LOCKS space id 55 page no 4 n bits 72 index `uk_name` of table `d1`.`t1` trx id 330A lock mode S waiting Record lock, heap no 2 PHYSICAL RECORD: n_fields 3; compact format; info bits 0 0: len 1; hex 31; asc 1;; 1: len 1; hex 31; asc 1;; 2: len 4; hex 80000001; asc ;; *** WE ROLL BACK TRANSACTION (2)
怎么样解决这样的问题呢?
一个可行的办法是在应用层排序以后再插入
总结
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